If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-33x+65=0
a = 4; b = -33; c = +65;
Δ = b2-4ac
Δ = -332-4·4·65
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-7}{2*4}=\frac{26}{8} =3+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+7}{2*4}=\frac{40}{8} =5 $
| 20X36+2x=3X-17 | | 6x+4=-47 | | x-5/3-x+1/4=2x-3/4-1/2 | | 25^x+1=4^2x+2 | | 6m+8=33 | | 2x=-35x-126=6 | | 6x-11=8x-27 | | 6a+9=2 | | x+5/2-3x-4=x/2+23/6 | | |4n+2|=32 | | (8+9+12+x)/4=10 | | (2-9x)^2=6 | | 8a+11=15 | | 5/4/x=25 | | 12a+5=8 | | 0/x=4 | | 4-2(3-x)=7-8 | | 3^2n=27^4 | | 3y-10y=6y+20 | | 1/4y+5=1/9y | | 9^x-27=0 | | 15=2πr | | 8a+5=9 | | 3/4x=144 | | 4−2(3−x)=7−x | | 16b=3/4 | | 5(x+2)-(3x-5)=29 | | 7+5h=3h–9 | | (t-5)^6-7(t-5)^3+12=0 | | x-8x=4-24 | | 5(x+2)-3x-5)=29 | | -4x+33+2x+81=180 |